0=-16x^2+14x+36

Solution for 0=-16x^2+14x+36 equation:

0=-16x^2+14x+36

We move all terms to the left:

0-(-16x^2+14x+36)=0

We add all the numbers together, and all the variables

-(-16x^2+14x+36)=0

We get rid of parentheses

16x^2-14x-36=0

a = 16; b = -14; c = -36;
Δ = b2-4ac
Δ = -142-4·16·(-36)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-50}{2*16}=\frac{-36}{32}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+50}{2*16}=\frac{64}{32}
=2
$